\[ \frac{2x + 3}{4} = \frac{5x - 1}{6} \]
Pasos para resolver:
\[ \frac{3x - 4}{2} + 1 = \frac{5 - x}{3} \]
Pasos para resolver:
\[ 5x - \frac{7x - 1}{5} = 2x - 1 \]
Pasos para resolver:
\[ \frac{2(x - 1)}{3} = \frac{5(2 - x)}{7} + 1 \]
Pasos para resolver: