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<h1>Solución</h1>

$$\mathop {\lim }\limits_{\theta  \to \pi } {{sen\theta } \over {tg\theta }} = {{sen\pi } \over {tg\pi }} = {0 \over 0}$$
<p>Así,
$$\mathop {\lim }\limits_{\theta  \to \pi } {{sen\theta } \over {tg\theta }} = \mathop {\lim }\limits_{\theta  \to \pi } {{sen\theta } \over {{{sen\theta } \over {\cos \theta }}}} = \mathop {\lim }\limits_{\theta  \to \pi } \cos \theta  =  - 1$$
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