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<h1>Solución</h1>
 $$\frac{{{d^2}y}}{{d{x^2}}} = \frac{{3{t^2} - 12t + 3}}{{2{{\left( {t - 2} \right)}^3}}}$$
 <p>Puntos críticos $(5,4)$, $(-3,4)$ y $(-4,6)$.</p>



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