Sustituye en la función dada la xxx en la fórmula de f(x)f(x)f(x).
Apartado a
f(−2)=3(−2)2+2(−2)−1=12−4−1=7f (−2) = 3(−2)^2 + 2(−2) − 1 = 12 − 4 − 1 = 7f(−2)=3(−2)2+2(−2)−1=12−4−1=7
Apartado b
f(2)=3⋅22+2⋅2−1=12+4−1=15f ( 2) = 3 \cdot 2^2 + 2\cdot 2 − 1 = 12+4-1=15f(2)=3⋅22+2⋅2−1=12+4−1=15
Apartado c
f(a+h)=3(a+h)2+2(a+h)−1=3(a2+2ah+h2)+2a+2h−1f (a + h) = 3(a + h)^2 + 2(a + h) − 1 = 3(a^2 + 2ah + h^2)+ 2a + 2h − 1f(a+h)=3(a+h)2+2(a+h)−1=3(a2+2ah+h2)+2a+2h−1
=3a2+6ah+3h2+2a+2h−1=3a^2 + 6ah + 3h^2 + 2a + 2h − 1=3a2+6ah+3h2+2a+2h−1