a. C′(x)=0.0003x2−0.04x+3C'(x)=0.0003x^2-0.04x+3C′(x)=0.0003x2−0.04x+3
b. dCdt=100⋅(0.0003x2−0.04x+3){{dC} \over {dt}} = 100 \cdot \left( {0.0003{x^2} - 0.04x + 3} \right)dtdC=100⋅(0.0003x2−0.04x+3)
c. Aproximadamente 90,30090,30090,300 por semana.