Solución
d
y
d
x
=
2
csc
2
x
(
1
+
cot
x
)
2
{{dy} \over {dx}} = {{2{{\csc }^2}x} \over {{{\left( {1 + \cot x} \right)}^2}}}
d
x
d
y
=
(
1
+
cot
x
)
2
2
csc
2
x