Solución
h
′
(
x
)
=
3
f
′
(
x
)
(
g
(
x
)
+
2
)
−
3
f
(
x
)
g
′
(
x
)
(
g
(
x
)
+
2
)
2
h'\left( x \right) = {{3f'\left( x \right)\left( {g\left( x \right) + 2} \right) - 3f\left( x \right)g'\left( x \right)} \over {{{\left( {g\left( x \right) + 2} \right)}^2}}}
h
′
(
x
)
=
(
g
(
x
)
+
2
)
2
3
f
′
(
x
)
(
g
(
x
)
+
2
)
−
3
f
(
x
)
g
′
(
x
)