Solución
f
′
(
x
)
=
270
x
4
+
39
(
x
+
1
)
2
f'\left( x \right) = 270{x^4} + {{39} \over {{{\left( {x + 1} \right)}^2}}}
f
′
(
x
)
=
270
x
4
+
(
x
+
1
)
2
39