Solución
Falso; $\mathop {\lim }\limits_{x \to 6} f\left( x \right)$ DNE ya que
$$\mathop {\lim }\limits_{x \to {6^ - }} f\left( x \right) = 2 \ne 5 = \mathop {\lim }\limits_{x \to {6^ + }} f\left( x \right)$$