Solución
$$\mathop {\lim }\limits_{x \to - 5} {{1 + g\left( x \right)} \over {f\left( x \right)}} = {{1 + \mathop {\lim }\limits_{x \to - 5} g\left( x \right)} \over {\mathop {\lim }\limits_{x \to - 5} f\left( x \right)}} = {{2 + 0} \over 2} = 1$$