Solución
lim
x
→
−
5
1
+
g
(
x
)
f
(
x
)
=
1
+
lim
x
→
−
5
g
(
x
)
lim
x
→
−
5
f
(
x
)
=
2
+
0
2
=
1
\mathop {\lim }\limits_{x \to - 5} {{1 + g\left( x \right)} \over {f\left( x \right)}} = {{1 + \mathop {\lim }\limits_{x \to - 5} g\left( x \right)} \over {\mathop {\lim }\limits_{x \to - 5} f\left( x \right)}} = {{2 + 0} \over 2} = 1
x
→
−
5
lim
f
(
x
)
1
+
g
(
x
)
=
x
→
−
5
lim
f
(
x
)
1
+
x
→
−
5
lim
g
(
x
)
=
2
2
+
0
=
1