Solución
lim
x
→
6
[
(
x
+
1
)
f
(
x
)
]
=
(
lim
x
→
6
(
x
+
1
)
)
(
lim
x
→
6
f
(
x
)
)
=
28
\mathop {\lim }\limits_{x \to 6} \left[ {\left( {x + 1} \right)f\left( x \right)} \right] = \left( {\mathop {\lim }\limits_{x \to 6} \left( {x + 1} \right)} \right)\left( {\mathop {\lim }\limits_{x \to 6} f\left( x \right)} \right) = 28
x
→
6
lim
[
(
x
+
1
)
f
(
x
)
]
=
(
x
→
6
lim
(
x
+
1
)
)
(
x
→
6
lim
f
(
x
)
)
=
28