Ejercicios propuestos - Capítulo V

Método de los nodos

1. FAC=375  lbF_{AC} = 375\;lb, FBC=780  lbF_{BC} = 780\;lb, FAB=300  lbF_{AB} = 300\;lb

3. FAB=FBC=31.5  kipsF_{AB} = F_{BC} = 31.5\;kips (T), FAD=335.7  kipsF_{AD} = 335.7\;kips (C), FBD=10.8  kipsF_{BD} = 10.8\;kips (C), FCD=33.3  kipsF_{CD} = 33.3\;kips (C)

5. FAD=318  lbF_{AD} = 318\; lb (C), FAB=225  lbF_{AB} = 225\; lb (T), FBC=225  lbF_{BC} = 225\; lb (T), FBD=0F_{BD} = 0, FCD=318  lbF_{CD} = 318\; lb (T)

7. FDC=1.34  kNF_{DC} = 1.34\; kN (C), FDE=1.20  kNF_{DE} = 1.20\; kN (T), FCE=0F_{CE} = 0, FCB=1.34  kNF_{CB} = 1.34\; kN (C), FEB=1.27  kNF_{EB} = 1.27\; kN (C), FEA=2.10  kNF_{EA} = 2.10\; kN (T)

9. FAD=849  lbF_{AD} = 849\; lb (C), FAB=600  lbF_{AB} = 600\; lb (T), FBD=400  lbF_{BD} = 400\; lb (C), FBC=600  lbF_{BC} = 600\; lb (T), FDC=1130  lbF_{DC} = 1130\; lb (T), FDE=1600  lbF_{DE} = 1600\; lb (C)

11. FCB=8  kNF_{CB} = 8\; kN (T), FCD=6.93  kNF_{CD} = 6.93\; kN (C), FDE=6.93  kNF_{DE} = 6.93\; kN (C), FDB=4  kNF_{DB} = 4\; kN (T), FBE=4  kNF_{BE} = 4\; kN (C), FBA=12  kNF_{BA} = 12\; kN (T)

13. FAB=FFH=1500  lbF_{AB} = F_{FH} = 1500\; lb (C), FAC=FCE=FEG=FGH=1200  lbF_{AC} = F_{CE} = F_{EG} = F_{GH} = 1200\; lb (T), FBC=FFG=FBD=FDF=1000  lbF_{BC} = F_{FG} = F_{BD} = F_{DF} = 1000\; lb (C), FBE=FEF=500  lbF_{BE} = F_{EF} = 500\; lb (C), FDE=600  lbF_{DE} = 600\; lb (T)

Método de las secciones

14. FCF=1980  lbF_{CF} = 1980\; lb (T), FFE=800  lbF_{FE} = 800\; lb (T), FBC=2200  lbF_{BC} = 2200\; lb (T)

15. FEF=600  lbF_{EF} = 600\; lb (C),FCF=346  lbF_{CF} = 346\; lb (T), FBC=346  lbF_{BC} = 346\; lb (T)

16. FBD=216  kNF_{BD} = 216\; kN (T), FDE=270  kNF_{DE} = 270\; kN (T)