Respuestas - Sección 3.4

Aquí encontrarás las respuestas a todos los ejercicios de la sección 3.4

  1. y2=−e−x\hspace{0.5cm}y_2=-e^{-x}

y=c1xe−x+c2e−x\hspace{0.3cm}y=c_1xe^{-x}+c_2e^{-x}

  1. y2=14sen4x\hspace{0.5cm}y_2=\dfrac{1}{4}sen{4x}

y=c1cos4x+c2sen4x\hspace{0.3cm}y=c_1cos{4x}+c_2sen{4x}

  1. y2=−65e−x2\hspace{0.5cm}y_2=-\dfrac{6}{5}e^{-\frac{x}{2}}

y=c1ex3+c2e−x2\hspace{0.3cm}y=c_1e^{\frac{x}{3}}+c_2e^{-\frac{x}{2}}

  1. y2=xe2x\hspace{0.5cm}y_2=xe^{2x}

y=c1=e2x+c2xe2x\hspace{0.3cm}y=c_1=e^{2x}+c_2xe^{2x}

  1. y2=−1\hspace{0.5cm}y_2=-1

y=c1ln⁡∣x∣+c2\hspace{0.3cm}y=c_1\ln \left| x\right|+c_2

  1. y2=−x12\hspace{0.5cm}y_2=-x^{\frac{1}{2}}

y=c1x12ln⁡∣x∣+c2x12\hspace{0.3cm}y=c_1x^{\frac{1}{2}}\ln \left| x\right|+c_2x^{\frac{1}{2}}

  1. y2=−xcos(ln⁡∣x∣)\hspace{0.5cm}y_2=-xcos(\ln \left| x\right|)

y=c1xsen(ln⁡∣x∣)+c2xcos(ln⁡∣x∣)\hspace{0.3cm}y=c_1xsen(\ln \left| x\right|)+c_2xcos(\ln \left| x\right|)

  1. y2=5sen(15ln⁡∣x∣)\hspace{0.5cm}y_2=5sen \left( \dfrac {1}{5}\ln \left| x\right| \right)

y=c1cos(15ln⁡∣x∣)+c2sen(15ln⁡∣x∣)\hspace{0.2cm}y=c_1cos \left( \dfrac {1}{5}\ln \left| x\right| \right)+c_2sen \left( \dfrac {1}{5}\ln \left| x\right| \right)

  1. y2=x2sen(ln⁡∣x∣)\hspace{0.5cm}y_2=x^2sen(\ln \left| x\right|)

y=c1x2cos(ln⁡∣x∣)+c2x2sen(ln⁡∣x∣)\hspace{0.2cm}y=c_1x^2cos(\ln \left| x\right|)+c_2x^2sen(\ln \left| x\right|)

  1. y2=x4sen(5ln⁡∣x∣)\hspace{0.5cm}y_2=x^4sen(5\ln \left| x\right|)

y=c1x4cos(5ln⁡∣x∣)+c2x4sen(5ln⁡∣x∣)\hspace{0.2cm}y=c_1x^4cos(5\ln \left| x\right|)+c_2x^4sen(5\ln \left| x\right|)