Respuestas - Capítulo 2

Aquí encontrarás las respuestas a todos los ejercicios del capítulo 2

  1. $\hspace{0.2cm}y=\sqrt{x-ln{\left|x+1\right|}+c}$

  1. $\hspace{0.2cm}c=\frac{x^4}{4}+xy^3$

    1. $\hspace{0.2cm}y=\sqrt{c\left(4+x^2\right)-2}$

      1. $\hspace{0.2cm}y={cos}^{-1}{\left(\frac{1}{2}x+\frac{1}{4}sen2x+c\right)}$

      1. $\hspace{0.2cm}y=\frac{1}{2}\left(x^2-1\right)+\frac{c}{e^{x^2}}$

        1. $\hspace{0.2cm}c=\frac{x^2}{y}$

          1. $\hspace{0.2cm}c=y^2+7xy+x^2$

          1. $\hspace{0.2cm}y=\sqrt{\frac{4}{3}x^4+\frac{c}{x^2}}$

            1. $\hspace{0.2cm}\frac{y^2}{2}+2y+ln{\left|y\right|}=\frac{x^3ln{\left|x\right|}}{3}-\frac{x^3}{9}+c$

              1. $\hspace{0.2cm}c=x^3y+xe^y-y^2$

              1. $\hspace{0.2cm}y=\sqrt[3]{1+\frac{c}{e^{\frac{3}{2}x^2}}}$

                1. $\hspace{0.2cm}e^\frac{2x}{y}=8ln{\left|y\right|}+c$

                  1. $\hspace{0.2cm} y=sec{x}+ccsc{x}$

                  1. $\hspace{0.2cm}e^y+ye^{-y}+e^{-y}=2cos{x}+c$

                    1. $\hspace{0.2cm}c=e^xseny+2ycos{x}$

                      1. $\hspace{0.2cm}e^{-y^2}=\frac{1}{3}e^{2x^3}+c$

                      1. $\hspace{0.2cm}yln{\left|\frac{x}{y}\right|}=-e$

                        1. $\hspace{0.2cm}ln{\left|x\right|}+1=e^\frac{y}{x}$

                          1. $\hspace{0.2cm}3=e^x+xy+2y+ye^y-e^y$

                          1. $\hspace{0.2cm}2x^4=x^2+y^2$

                            1. $\hspace{0.2cm}2248$ Habitantes

                            1. $\hspace{0.2cm}t=6.3\ Años \ \land\ t=7.3\ Años$

                              1. $\hspace{0.2cm}t=672.3 $ Años

                                1. $\hspace{0.2cm} x=\frac{1}{150}e^{-0.05783t}$

                                1. $\hspace{0.2cm}t=55808.4$ Años

                                  1. $\hspace{0.2cm}x=0.0009765\ Io$

                                    1. $\hspace{0.2cm}t=72.28$ minutos

                                    1. $\hspace{0.2cm}x = 44.52$ dolares

                                      1. $\hspace{0.2cm}t=52$ minutos

                                        1. $\hspace{0.2cm} T=65.33^{\circ }C \ \land\ t=139.2\ minutos$

                                        1. $\hspace{0.2cm}T=324^{\circ }F$

                                          1. $\hspace{0.2cm}T=58.5^{\circ }F$

                                            1. $\hspace{0.2cm}t=28.88$ segundos

                                            1. $\hspace{0.2cm}A=100-t-\frac{80}{100^8}\left(100-t\right)^8$ El tanque se vacía en $100$ minutos