Solución
∬
S
(
r
o
t
F
⋅
N
)
d
S
=
−
3
π
\iint_S (rot\;\bold{F}\cdot\bold{N})dS = -3\pi
∬
S
(
ro
t
F
⋅
N
)
d
S
=
−
3
π