Solución
∬
S
(
r
o
t
F
⋅
N
)
d
S
=
−
1
6
\iint_S (rot \;\bold{F}\cdot\bold{N})dS =-\frac16
∬
S
(
ro
t
F
⋅
N
)
d
S
=
−
6
1