Solución

a. Ix=π32,Iy=π8,I0=5π32I_x = \frac{\pi}{32}, I_y = \frac{\pi}{8}, I_0 = \frac{5\pi}{32} b. Rx=14,Ry=12,R0=54R_x = \frac{1}{4}, R_y = \frac{1}{2}, R_0 = \frac{\sqrt{5}}{4}