∫02π∫24∫−16−r216−r2rdzdrdθ\int_0^{2\pi}\int_2^4\int_{-\sqrt{16-r^2}}^{\sqrt{16-r^2}} r dzdrd\theta∫02π∫24∫−16−r216−r2rdzdrdθ ∫π/55π/6∫02π∫2cscϕ4senρdρdθdϕ\int_{\pi/5}^{5\pi/6}\int_0^{2\pi}\int_{2csc\phi}^4 sen\rho d\rho d\theta d\phi∫π/55π/6∫02π∫2cscϕ4senρdρdθdϕ