Solución

máxima: $f\bigg(\frac{3\sqrt{2}}{2}, 2\sqrt{2}\bigg) = 24, f\bigg(-\frac{3\sqrt{2}}{2}, -2\sqrt{2}\bigg) = 24$

Mínima: $f\bigg(-\frac{3\sqrt{2}}{2}, 2\sqrt{2}\bigg) = -24, f\bigg(\frac{3\sqrt{2}}{2}, -2\sqrt{2}\bigg) = -24$