Solución

máxima: f(322,22)=24,f(−322,−22)=24f\bigg(\frac{3\sqrt{2}}{2}, 2\sqrt{2}\bigg) = 24, f\bigg(-\frac{3\sqrt{2}}{2}, -2\sqrt{2}\bigg) = 24

Mínima: f(−322,22)=−24,f(322,−22)=−24f\bigg(-\frac{3\sqrt{2}}{2}, 2\sqrt{2}\bigg) = -24, f\bigg(\frac{3\sqrt{2}}{2}, -2\sqrt{2}\bigg) = -24