Solución

Sustituya los componentes de los vectores en la Ecuación 2.9:

u×v=1,2,5×4,0,3=p2q3p3q2,p1q3p3q1,p1q2p2q1=2(3)5(0),(1)(3)+5(4),(1)(0)2(4)=6,17,8\begin{aligned} \bold{u} \times \bold{v} &= \lang −1,2,5\rang \times \lang 4,0,−3\rang\\ &= \lang p_2 \cdot q_3 − p_3 \cdot q_2, p_1 \cdot q_3 − p_3 \cdot q_1, p_1 \cdot q_2 − p_2 \cdot q_1\rang\\ &= \lang 2(−3)−5(0),−(−1)(−3)+5(4),(−1)(0)−2(4)\rang\\ &= \lang −6,17,−8\rang \end{aligned}