Solución
N
(
0
)
=
⟨
2
6
,
1
6
,
1
6
⟩
\bold{N}(0) = \bigg\lang \frac{2}{\sqrt{6}}, \frac{1}{\sqrt{6}}, \frac{1}{\sqrt{6}}\bigg\rang
N
(
0
)
=
⟨
6
2
,
6
1
,
6
1
⟩