Solución

a. r=1,0,5+t5,0,2,tR\bold{r}=\lang −1,0,5\rang+t\lang 5,0,−2\rang, t\isin\Reals
b. x=1+5t,y=0,z=52t,tRx=−1+5t,y=0,z=5−2t, t\isin\Reals
c. x+15=z52,y=0\frac{x+1}{5}=\frac{z−5}{−2},y=0
d. x=1+5t,y=0,z=52t,t[0,1]x=−1+5t,y=0,z=5−2t, t\isin[0,1]