a. r=⟨−1,0,5⟩+t⟨5,0,−2⟩,t∈R\bold{r}=\lang −1,0,5\rang+t\lang 5,0,−2\rang, t\isin\Realsr=⟨−1,0,5⟩+t⟨5,0,−2⟩,t∈R b. x=−1+5t,y=0,z=5−2t,t∈Rx=−1+5t,y=0,z=5−2t, t\isin\Realsx=−1+5t,y=0,z=5−2t,t∈R c. x+15=z−5−2,y=0\frac{x+1}{5}=\frac{z−5}{−2},y=05x+1=−2z−5,y=0 d. x=−1+5t,y=0,z=5−2t,t∈[0,1]x=−1+5t,y=0,z=5−2t, t\isin[0,1]x=−1+5t,y=0,z=5−2t,t∈[0,1]