Solución

a. a+b=3i+4j,a+b=3,4\bold{a} + \bold{b} = 3\bold{i} + 4\bold{j}, \bold{a}+ \bold{b} = \lang 3, 4\rang
b. ab=i2j,ab=1,2\bold{a} − \bold{b} = \bold{i} − 2\bold{j}, \bold{a} − \bold{b} = \lang 1, −2\rang
c. Las respuestas variarán
d. 2a=4i+2j,2a=4,2,b=i3j,b=1,3,2ab=3ij,2ab=3,12\bold{a} = 4\bold{i} + 2\bold{j}, 2\bold{a} = \lang 4, 2\rang, −\bold{b}\\ = −\bold{i} − 3\bold{j}, −\bold{b} = \lang − 1, −3\rang, 2\bold{a} − \bold{b} = 3\bold{i} − \bold{j}, 2\bold{a} − \bold{b} = \lang 3, −1\rang