Solución
C
=
2
π
(
5
)
=
10
π
y
∫
0
π
10
d
θ
=
10
π
C=2\pi(5)=10\pi \;y\;\int_0^{\pi}10d\theta = 10\pi
C
=
2
π
(
5
)
=
10
π
y
∫
0
π
10
d
θ
=
10
π