Solución
C
=
2
π
(
3
2
)
=
3
π
y
∫
0
π
3
d
θ
=
3
π
C=2\pi\left(\frac32\right)=3\pi\;y\;\int_0^{\pi}3d\theta = 3\pi
C
=
2
π
(
2
3
)
=
3
π
y
∫
0
π
3
d
θ
=
3
π