Solución
A
=
π
2
y
1
2
∫
0
π
(
1
+
2
s
e
n
θ
c
o
s
θ
)
d
θ
=
π
2
A=\frac{\pi}{2}\;y\;\frac12\int_0^{\pi} (1+2sen\theta cos\theta)d\theta = \frac{\pi}{2}
A
=
2
π
y
2
1
∫
0
π
(
1
+
2
se
n
θ
cos
θ
)
d
θ
=
2
π